calculate stresses in helical compression springs.
2023-02-09 17:51:22
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Inputs |
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H1 |
0.4 |
0.4 |
0.4 |
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H2 |
0.368 |
0.368 |
0.368 |
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Spring Description |
proposed |
Shipped to Phillips |
Standard |
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Spring Number = |
10249111 |
10249210 |
10249241 |
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FL = Free Length (in) = |
0.4375 |
0.5625 |
0.4375 |
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k = Spring Constant (lb/in) = |
5.8 |
2.2 |
2.9 |
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SH = Solid Height (in) = |
0.183 |
0.172 |
0.138 |
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d = Wire kendieczanesi.com Diameter (in) = |
0.012 |
0.01 |
0.01 |
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OD = Outside Diameter (in) = |
0.088 |
0.088 |
0.088 |
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G: Torsion modulus (psi) = |
1.15E+07 |
1.15E+07 |
1.15E+07 |
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Calculations |
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Ssy = est. torsional yeild strength (psi) = |
161,783 |
166,147 |
166,147 |
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DH = H1-H2 (in) = |
0.032 |
0.032 |
0.032 |
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FS2 (lb) per spring = |
0.40 |
0.43 |
0.20 |
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H2 (in) = |
0.368 |
0.368 |
0.368 |
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% compression at H2 = |
27% |
50% |
23% |
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H1 (in) = |
0.400 |
0.400 |
0.400 |
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% compression at H1 = |
15% |
42% |
13% |
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FS1 (lb) per spring at H1 = |
0.22 |
0.36 |
0.11 |
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F1 (lb) = |
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% diff (F2-F1)/F2 = |
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ratio: Deflection to Free Length = |
0.16 |
0.35 |
0.16 |
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ratio: Free Length to Mean Dia. = |
5.76 |
7.21 |
5.61 |
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No Buckling Zone(Yes/No) |
yes |
no |
Yes |
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D = mean diameter (OD-d) (in) = |
0.076 |
0.078 |
0.078 |
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C = Spring Index D/d = |
6.3 |
7.8 |
7.8 |
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K: Wahl correction factor = |
1.2 |
1.2 |
1.2 |
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tmax = max stress in wire (psi) = |
55,879 |
101,067 |
47,605 |
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N = est. no. of active coils = |
11.7 |
13.8 |
10.4 |
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FS = safety factor = Ssy/tmax = |
2.9 |
1.6 |
3.5 |
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W = weight of the spring (lb) = |
0.000122 |
0.000102 |
7.76E-05 |
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f = fundamental frequency = (hz) = |
2141.628 |
1440.667 |
1899.061 |
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no. of times greater than freq. of motion = |
308 |
207 |
273 |
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